Consult the table of standard electrode potentials and suggest three substances that can oxidise ferrous ions under suitable conditions.
(N/A) Substances that are stronger oxidizing agents than ferrous ions can oxidize ferrous ions.
The oxidation reaction is: $Fe^{2+} \to Fe^{3+} + e^{-}; E^{\Theta} = -0.77 \ V$.
This implies that any substance with a standard reduction potential higher than $+0.77 \ V$ can oxidize ferrous ions $(Fe^{2+})$ to ferric ions $(Fe^{3+})$.
Three substances that satisfy this condition are $F_{2}$ $(E^{\Theta} = +2.87 \ V)$,$Cl_{2}$ $(E^{\Theta} = +1.36 \ V)$,and $O_{2}$ $(E^{\Theta} = +1.23 \ V)$.
The oxidation reaction is: $Fe^{2+} \to Fe^{3+} + e^{-}; E^{\Theta} = -0.77 \ V$.
This implies that any substance with a standard reduction potential higher than $+0.77 \ V$ can oxidize ferrous ions $(Fe^{2+})$ to ferric ions $(Fe^{3+})$.
Three substances that satisfy this condition are $F_{2}$ $(E^{\Theta} = +2.87 \ V)$,$Cl_{2}$ $(E^{\Theta} = +1.36 \ V)$,and $O_{2}$ $(E^{\Theta} = +1.23 \ V)$.
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