Correct order for nucleophilic addition react | vedclass

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(A) Nucleophilic addition reactivity depends on the electrophilicity of the carbonyl carbon.$1.$ Aldehydes are more reactive than ketones due to less

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$2 > 3 > 4 > 1$

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(A) Nucleophilic addition reactivity depends on the electrophilicity of the carbonyl carbon.$1.$ Aldehydes are more reactive than ketones due to less steric hindrance and lower electronic repulsion.$2.$ Electron-donating groups $(EDG)$ decrease the electrophilicity of the carbonyl carbon,thereby decreasing reactivity.$3.$ The order of electron-donating strength is: $CH_{3}O$ (strong $+M$) $> CH_{3}$ (weak $+I$) $> H$ (no effect).$4.$ Comparing the compounds:$(1)$ $C_{6}H_{5}COC_{6}H_{5}$ (Ketone,least reactive)$(2)$ $C_{6}H_{5}CHO$ (Benzaldehyde,most reactive among these)$(3)$ $p-CH_{3}C_{6}H_{4}CHO$ (Aldehyde with $+I$ group)$(4)$ $p-CH_{3}OC_{6}H_{4}CHO$ (Aldehyde with $+M$ group)Thus,the reactivity order is: $2 > 3 > 4 > 1$.

Correct order for nucleophilic addition reaction :
$(1)$ $C_{6}H_{5}COC_{6}H_{5}$
$(2)$ $C_{6}H_{5}CHO$
$(3)$ $p-CH_{3}C_{6}H_{4}CHO$
$(4)$ $p-CH_{3}OC_{6}H_{4}CHO$

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Correct order for nucleophilic addition reaction :$(1)$ $C_{6}H_{5}COC_{6}H_{5}$$(2)$ $C_{6}H_{5}CHO$$(3)$ $p-CH_{3}C_{6}H_{4}CHO$$(4)$ $p-CH_{3}OC_{6}H_{4}CHO$