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(D) Atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge. In option $A$,the order shoul

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$I > P > S > Cl$

Vedclass · Answer

(D) Atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge. In option $A$,the order should be $Li > Be > B > C$. In option $B$,the order should be $B > C > N > O$. In option $C$,the order should be $Na > Mg > Si > P$. In option $D$,$I$ is in the $5^{th}$ period,while $P$,$S$,and $Cl$ are in the $3^{rd}$ period. Since atomic radius increases down a group,$I$ has a larger radius than the elements of the $3^{rd}$ period. Within the $3^{rd}$ period,the order is $P > S > Cl$. Therefore,the correct order is $I > P > S > Cl$.

Which of the following represents the correct order of atomic radius?

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