The correct order of base strength in benzene | vedclass

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(C) In a non-polar solvent like benzene,the solvation effect (which is significant in water) is absent.Therefore,the basic strength is primarily deter

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$III > II > I$

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(C) In a non-polar solvent like benzene,the solvation effect (which is significant in water) is absent.Therefore,the basic strength is primarily determined by the inductive effect ($+I$ effect) of the alkyl groups.As the number of ethyl groups increases,the electron density on the nitrogen atom increases due to the $+I$ effect,making the lone pair more available for donation.The order of basic strength based on the $+I$ effect is: tertiary amine $(III)$ > secondary amine $(II)$ > primary amine $(I)$.Thus,the correct order is $III > II > I$.

The correct order of base strength in benzene as a solvent for the given amines is:
$I: CH_3CH_2NH_2$
$II: (CH_3CH_2)_2NH$
$III: (CH_3CH_2)_3N$

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The correct order of base strength in benzene as a solvent for the given amines is:$I: CH_3CH_2NH_2$$II: (CH_3CH_2)_2NH$$III: (CH_3CH_2)_3N$