The correct order of bond angle is:

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Question

(A) The bond angles for the given molecules are as follows:$OF_2$: $103.2^{\circ}$$H_2O$: $104.5^{\circ}$$NH_3$: $107^{\circ}$$Cl_2O$: $111^{\circ}$In

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$OF_2 < H_2O < NH_3 < Cl_2O$

Vedclass · Answer

(A) The bond angles for the given molecules are as follows:$OF_2$: $103.2^{\circ}$$H_2O$: $104.5^{\circ}$$NH_3$: $107^{\circ}$$Cl_2O$: $111^{\circ}$In $OF_2$,the high electronegativity of $F$ pulls the bonding electron pairs away from the central $O$ atom,reducing the bond angle due to lone pair-lone pair repulsion.In $Cl_2O$,the large size of $Cl$ atoms causes significant steric repulsion,which increases the bond angle to $111^{\circ}$,making it the largest among these.Thus,the correct order is $OF_2 < H_2O < NH_3 < Cl_2O$.

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