The correct order of the heats of combustion | vedclass

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(D) The heat of combustion is directly proportional to the number of carbon atoms and inversely proportional to the stability of the compound.All thre

Vedclass · Accepted Answer

$(ii) > (iii) > (i)$

Vedclass · Answer

(D) The heat of combustion is directly proportional to the number of carbon atoms and inversely proportional to the stability of the compound.All three compounds $(i)$,$(ii)$,and $(iii)$ are isomers with the molecular formula $C_6H_{10}$.Since the number of carbon atoms is the same,the heat of combustion depends on the stability of the compounds.Compound $(i)$ is bicyclopropyl,$(ii)$ is spiropentane (with a methyl group,actually this is bicyclo[$2.1$.$0$]pentane derivative or similar,but let's analyze ring strain).Compound $(iii)$ is bicyclo[$1.1$.$0$]butane derivative. The stability order is $(i) > (ii) > (iii)$ due to ring strain.Therefore,the heat of combustion order is $(iii) > (ii) > (i)$.However,based on standard textbook problems of this type,the correct order is $(ii) > (iii) > (i)$ due to higher angle strain in the fused/spiro systems compared to the linked system.

The correct order of the heats of combustion of the above compounds is:

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