Correct statements regarding alkyl halides ($R-X$) among the following are:
A. Alcohol being less polar solvent as compared to water, alcoholic $KOH$ favours elimination reaction with $R-X$.
B. Order of reactivity towards $S_N1$ mechanism is $C_6H_5-CH_2-Cl > C_6H_5-CHCl-C_6H_5$.
C. Non substituted aryl halides exhibit properties similar to alkyl halides.
D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne.
E. $R-Cl$ can be prepared by reacting $R-OH$ with $SOCl_2$ but $Ar-Cl$ cannot be prepared by reacting $Ar-OH$ with $SOCl_2$.
Choose the correct answer from the options given below:
- AA, B and C Only
- BB and D Only
- CA and E Only
- DD and E Only
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Similar Questions
The number of possible isomeric products formed when $3$-chloro-$1$-butene reacts with $HCl$ through carbocation formation is $.............$.
Draw the structures of major monohalo products in each of the following reactions:
Easy
View SolutionWhat is the product of the following reaction?
Medium
View SolutionWrite the structure of the major organic product in each of the following reactions:
$(i)$ $CH_3-CH_2-CH_2-Cl + NaI \xrightarrow[\text{heat}]{\text{acetone}}$
$(ii)$ $CH_3-C(CH_3)_2-Br + KOH \xrightarrow[\text{heat}]{\text{ethanol}}$
$(iii)$ $CH_3-CH(Br)-CH_2-CH_3 + NaOH \xrightarrow{\text{water}}$
$(iv)$ $CH_3-CH_2-Br + KCN \xrightarrow{\text{aq. ethanol}}$
$(v)$ $C_6H_5-ONa + C_2H_5-Cl \longrightarrow$
$(vi)$ $CH_3-CH_2-CH_2-OH + SOCl_2 \longrightarrow$
$(vii)$ $CH_3-CH_2-CH=CH_2 + HBr \xrightarrow{\text{peroxide}}$
$(viii)$ $CH_3-CH=C(CH_3)_2 + HBr \longrightarrow$
$(i)$ $CH_3-CH_2-CH_2-Cl + NaI \xrightarrow[\text{heat}]{\text{acetone}}$
$(ii)$ $CH_3-C(CH_3)_2-Br + KOH \xrightarrow[\text{heat}]{\text{ethanol}}$
$(iii)$ $CH_3-CH(Br)-CH_2-CH_3 + NaOH \xrightarrow{\text{water}}$
$(iv)$ $CH_3-CH_2-Br + KCN \xrightarrow{\text{aq. ethanol}}$
$(v)$ $C_6H_5-ONa + C_2H_5-Cl \longrightarrow$
$(vi)$ $CH_3-CH_2-CH_2-OH + SOCl_2 \longrightarrow$
$(vii)$ $CH_3-CH_2-CH=CH_2 + HBr \xrightarrow{\text{peroxide}}$
$(viii)$ $CH_3-CH=C(CH_3)_2 + HBr \longrightarrow$
Easy
View SolutionAssertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.
Reason : Alkyl halides are less reactive than acyl halides.
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