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(A) In $[Co(CN)_6]^{3-}$,the cobalt ion is in the $+3$ oxidation state,which corresponds to a $3d^6$ configuration.Since $CN^-$ is a strong field liga

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$- 2.4 \Delta_0 + 3P$

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(A) In $[Co(CN)_6]^{3-}$,the cobalt ion is in the $+3$ oxidation state,which corresponds to a $3d^6$ configuration.Since $CN^-$ is a strong field ligand,it causes pairing of electrons,resulting in a low-spin complex.All $6$ electrons occupy the $t_{2g}$ orbitals,and $0$ electrons occupy the $e_g$ orbitals.The crystal field stabilization energy $(CFSE)$ is calculated as:$CFSE = (n_{t2g} 	imes -0.4 \Delta_0) + (n_{eg} 	imes 0.6 \Delta_0) + mP$Where $n_{t2g} = 6$,$n_{eg} = 0$,and $m$ is the number of extra electron pairs formed due to pairing.For $d^6$ low spin,$3$ pairs are formed,so $m = 3$.$CFSE = (6 	imes -0.4 \Delta_0) + (0 	imes 0.6 \Delta_0) + 3P = -2.4 \Delta_0 + 3P$.

Crystal field stabilization energy for complex $[Co(CN)_6]^{3-}$ will be

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