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Question

(B) The relationship between terminal potential difference $(V)$, $emf$ $(\varepsilon)$, current $(I)$, and internal resistance $(r)$ is given by: $V

Vedclass · Accepted Answer

$1.4$

Vedclass · Answer

(B) The relationship between terminal potential difference $(V)$, $emf$ $(\varepsilon)$, current $(I)$, and internal resistance $(r)$ is given by: $V = \varepsilon - Ir$.Rearranging, we get: $\varepsilon = V + Ir$.Using the values from the first two rows of the table:For row $1$: $\varepsilon = 1.0 + 0.08r \quad (1)$For row $2$: $\varepsilon = 0.5 + 0.18r \quad (2)$Equating $(1)$ and $(2)$: $1.0 + 0.08r = 0.5 + 0.18r$.Rearranging terms: $1.0 - 0.5 = 0.18r - 0.08r$.$0.5 = 0.1r$, which gives $r = 5 \ \Omega$.Substituting $r = 5 \ \Omega$ into equation $(1)$: $\varepsilon = 1.0 + 0.08(5) = 1.0 + 0.4 = 1.4 \ V$.

Order	$V \ (V)$	$I \ (A)$
$1$	$1.0$	$0.08$
$2$	$0.5$	$0.18$
$3$	$0.8$	$0.12$

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