Current through ABC and A^{prime} B^{prime} C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic field at point $P$ is produced by the segments $BC$ and $B^{\prime} C^{\prime}$.Segments $AB$ and $A^{\prime} B^{\prime}$ are directe

Vedclass · Accepted Answer

$B = \frac{\mu_0}{4 \pi} \left( \frac{2 I}{r} \right)$

Vedclass · Answer

(B) The magnetic field at point $P$ is produced by the segments $BC$ and $B^{\prime} C^{\prime}$.Segments $AB$ and $A^{\prime} B^{\prime}$ are directed towards and away from the axis containing $P$, so the magnetic field due to these segments at point $P$ is zero because $P$ lies on the line of these current elements.For the semi-infinite wire $BC$, the magnetic field at distance $r$ from the end $B$ is given by $B_1 = \frac{\mu_0 I}{4 \pi r}$.Similarly, for the semi-infinite wire $B^{\prime} C^{\prime}$, the magnetic field at distance $r$ from the end $B^{\prime}$ is $B_2 = \frac{\mu_0 I}{4 \pi r}$.Using the right-hand rule, both fields at $P$ point in the same direction (into the page).Therefore, the total magnetic field is $B = B_1 + B_2 = \frac{\mu_0 I}{4 \pi r} + \frac{\mu_0 I}{4 \pi r} = \frac{\mu_0}{4 \pi} \left( \frac{2 I}{r} \right)$.

Current through $ABC$ and $A^{\prime} B^{\prime} C^{\prime}$ is $I$. What is the magnetic field at $P$? $BP = PB^{\prime} = r$. (Here $C^{\prime} B^{\prime} PBC$ are collinear).

Similar Questions

Two points $A$ and $B$ on the axis of a circular current loop are at distances of $4 \ cm$ and $3 \sqrt{3} \ cm$ from the centre of the loop. If the ratio of the induced magnetic fields at points $A$ and $B$ is $216: 125$, the radius of the loop is (in $cm$)

$A$ linear small part of wire $PQ$ is situated on the $y$-axis from $y = -a/2$ to $y = +a/2$, and a current $I$ is flowing through it. The magnetic field produced due to wire $PQ$ at the point $y = +a$ will be:

Find the magnitude of the magnetic field at point $p$ due to the semi-infinite wire shown below.

$A$ wire shaped in a regular hexagon of side $2 \text{ cm}$ carries a current of $4 \text{ A}$. The magnetic field at the centre of the hexagon is

Vedclass Test Series

Exam Paper Generator

Online Exam Module