Currents flowing in each of the following cir | vedclass

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(C) In circuit $A$, both $p-n$ junction diodes are in forward bias. Hence, current flows through both branches. The total resistance $R_A$ is given by

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$4$ $A$, $2$ $A$

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(C) In circuit $A$, both $p-n$ junction diodes are in forward bias. Hence, current flows through both branches. The total resistance $R_A$ is given by $\frac{1}{R_A} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4}$, so $R_A = 2 \Omega$. Using Ohm's law, $I_A = \frac{V}{R_A} = \frac{8 	ext{ V}}{2 \Omega} = 4 	ext{ A}$.In circuit $B$, the upper diode is in forward bias, but the lower diode is in reverse bias. Therefore, no current flows through the lower branch. The current flows only through the upper branch with resistance $4 \Omega$. Using Ohm's law, $I_B = \frac{V}{R_B} = \frac{8 	ext{ V}}{4 \Omega} = 2 	ext{ A}$.Thus, the currents are $4 	ext{ A}$ and $2 	ext{ A}$ respectively.

Currents flowing in each of the following circuits $A$ and $B$ respectively are

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