Curved surface area of a right circular cylin | vedclass

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(A) Let the height of the right circular cylinder be $h$.The radius $(r)$ of the base of the cylinder is given as $0.7 \, m$.The curved surface area $

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$1$

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(A) Let the height of the right circular cylinder be $h$.The radius $(r)$ of the base of the cylinder is given as $0.7 \, m$.The curved surface area $(CSA)$ of the cylinder is given as $4.4 \, m^2$.The formula for the curved surface area of a cylinder is $CSA = 2 \pi r h$.Substituting the given values into the formula:$2 	imes \frac{22}{7} 	imes 0.7 	imes h = 4.4$Simplify the expression:$2 	imes 22 	imes 0.1 	imes h = 4.4$$4.4 	imes h = 4.4$Solving for $h$:$h = \frac{4.4}{4.4} = 1 \, m$.Therefore,the height of the cylinder is $1 \, m$.

Curved surface area of a right circular cylinder is $4.4 \, m^2$. If the radius of the base of the cylinder is $0.7 \, m$,find its height. (Take $\pi = \frac{22}{7}$) (in $, m$)

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