Decolourisation of acidified potassium permanganate occurs when $H_2O_2$ is added to it,this is due to

  • A
    Oxidation of $KMnO_4$
  • B
    Reduction of $KMnO_4$
  • C
    Both oxidation & reduction of $KMnO_4$
  • D
    None of the above

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Similar Questions

$I. \, H_2O_2 + O_3 \rightarrow H_2O + 2O_2$
$II. \, H_2O_2 + Ag_2O \rightarrow 2Ag + H_2O + O_2$
The role of hydrogen peroxide in the above reactions is respectively:

The dihedral angles in gaseous and solid phases of $H_2O_2$ molecule respectively are

$H_2O_2$ cannot oxidise

The reaction $H_2S + H_2O_2 \to S + 2H_2O$ manifests:

The normality of $10$ $V$ (volume) hydrogen peroxide is:

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