Define distance and displacement. $A$ body covers one complete revolution around a circular park of circumference $176 \, m$ in $4$ minutes. Find the displacement of the body after $6$ minutes.
(N/A) Distance: It is defined as the total path length covered by a body.
Displacement: It is defined as the shortest distance between the initial and final positions of a body.
Given that the circumference of the circular park is $176 \, m$. The body completes one revolution in $4$ minutes.
After $6$ minutes,the number of revolutions completed $= \frac{6}{4} = 1.5$ revolutions.
Since $1$ revolution brings the body back to the starting point,after $1.5$ revolutions,the body will be at a position diametrically opposite to the starting point.
Given $2 \pi r = 176 \, m$,where $r$ is the radius.
$r = \frac{176}{2 \pi} = \frac{176 \times 7}{2 \times 22} = 28 \, m$.
The displacement after $1.5$ revolutions is the diameter of the circular path.
Displacement $= 2r = 2 \times 28 = 56 \, m$.
Displacement: It is defined as the shortest distance between the initial and final positions of a body.
Given that the circumference of the circular park is $176 \, m$. The body completes one revolution in $4$ minutes.
After $6$ minutes,the number of revolutions completed $= \frac{6}{4} = 1.5$ revolutions.
Since $1$ revolution brings the body back to the starting point,after $1.5$ revolutions,the body will be at a position diametrically opposite to the starting point.
Given $2 \pi r = 176 \, m$,where $r$ is the radius.
$r = \frac{176}{2 \pi} = \frac{176 \times 7}{2 \times 22} = 28 \, m$.
The displacement after $1.5$ revolutions is the diameter of the circular path.
Displacement $= 2r = 2 \times 28 = 56 \, m$.
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