Class 12PhysicsMoving Charges and MagnetismThe Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion
EasyDefine the function of the small cylinder in the construction of a galvanometer.
(N/A) In a moving coil galvanometer,a soft iron cylinder is placed inside the coil. The primary functions of this cylinder are:
$1$. It increases the strength of the magnetic field by concentrating the magnetic flux lines through the coil due to its high permeability.
$2$. It makes the magnetic field radial,ensuring that the plane of the coil is always parallel to the magnetic field lines,regardless of the coil's orientation. This results in a linear relationship between the current and the deflection,i.e.,$\tau = NIAB \sin(90^{\circ}) = NIAB$.
$1$. It increases the strength of the magnetic field by concentrating the magnetic flux lines through the coil due to its high permeability.
$2$. It makes the magnetic field radial,ensuring that the plane of the coil is always parallel to the magnetic field lines,regardless of the coil's orientation. This results in a linear relationship between the current and the deflection,i.e.,$\tau = NIAB \sin(90^{\circ}) = NIAB$.
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Similar Questions
An ammeter with a resistance of $0.018 \, \Omega$ can measure $1 \, A$. What shunt resistance is required to enable it to measure $10 \, A$?
Medium
View Solution$A$ moving coil galvanometer has a coil with $175$ turns and an area of $1 \, cm^2$. It uses a torsion band with a torsion constant of $10^{-6} \, N \cdot m/rad$. The coil is placed in a magnetic field $B$ parallel to its plane. The coil deflects by $10^{\circ}$ for a current of $1 \, mA$. The value of $B$ (in Tesla) is approximately:
Explain the construction and principle of a moving coil galvanometer.
Difficult
View SolutionThe resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current up to $100\, A$. After an additional shunt has been connected to this ammeter,it becomes possible to measure currents up to $750\, A$ by this meter. The value of the shunt resistance is:
The current passing through the galvanometer is $4\%$ of the total current in the circuit. If the resistance of the galvanometer is $G$, the shunt resistance $S$ connected across the galvanometer is:
DifficultMHT CET 2026
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