Define the oxidation states of Mn in the prod | vedclass

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(A) In the given reaction: $3K_2MnO_4 + 2H_2O + 4CO_2 \rightarrow 2KMnO_4 + MnO_2 + 4KHCO_3$.The products containing $Mn$ are $KMnO_4$ and $MnO_2$.$1$

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$+7, +4$

Vedclass · Answer

(A) In the given reaction: $3K_2MnO_4 + 2H_2O + 4CO_2 \rightarrow 2KMnO_4 + MnO_2 + 4KHCO_3$.The products containing $Mn$ are $KMnO_4$ and $MnO_2$.$1$. In $KMnO_4$: Let the oxidation state of $Mn$ be $x$. Then,$1 + x + 4(-2) = 0$ $\Rightarrow x - 7 = 0$ $\Rightarrow x = +7$.$2$. In $MnO_2$: Let the oxidation state of $Mn$ be $y$. Then,$y + 2(-2) = 0$ $\Rightarrow y - 4 = 0$ $\Rightarrow y = +4$.Therefore,the oxidation states of $Mn$ in the products are $+7$ and $+4$.

Define the oxidation states of $Mn$ in the products of the given reaction:
$3K_2MnO_4 + 2H_2O + 4CO_2 \rightarrow 2KMnO_4 + MnO_2 + 4KHCO_3$

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Define the oxidation states of $Mn$ in the products of the given reaction:$3K_2MnO_4 + 2H_2O + 4CO_2 \rightarrow 2KMnO_4 + MnO_2 + 4KHCO_3$