Densities of two gases are in the ratio 1:2 a | vedclass

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(A) From the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$ and $d = \frac{m}{V}$,we get $P = \frac{dRT}{M}$.Assuming the molar masses $(M)$ of

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$1:1$

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(A) From the ideal gas equation,$PV = nRT$,where $n = \frac{m}{M}$ and $d = \frac{m}{V}$,we get $P = \frac{dRT}{M}$.Assuming the molar masses $(M)$ of the two gases are the same or comparing the pressure-density-temperature relationship for a given gas,the ratio is given by $\frac{P_1}{P_2} = \frac{d_1 T_1}{d_2 T_2}$.Given $\frac{d_1}{d_2} = \frac{1}{2}$ and $\frac{T_1}{T_2} = \frac{2}{1}$.Substituting these values: $\frac{P_1}{P_2} = \frac{1}{2} 	imes \frac{2}{1} = \frac{1}{1}$.Thus,the ratio of their pressures is $1:1$.

List-$I$	List-$II$
$(A)$ Viscosity	$(I)$ Critical temperature
$(B)$ Ideal gas behaviour	$(II)$ Isobars
$(C)$ Liquefaction of gases	$(III)$ Compressibility factor
$(D)$ Charles' law	$(IV)$ $kg \ s^{-2}$
	$(V)$ $kg \ m^{-1} \ s^{-1}$

Densities of two gases are in the ratio $1:2$ and their temperatures are in the ratio $2:1$,then the ratio of their respective pressures is

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