The density of an aqueous solution of 4% by m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: $4\%$ $NaOH$ by mass means $4\ g$ of $NaOH$ is present in $100\ g$ of solution.Mass of solute $(NaOH)$ $= 4\ g$.Molar mass of $NaOH = 23 +

Vedclass · Accepted Answer

$> 1\ m$

Vedclass · Answer

(C) Given: $4\%$ $NaOH$ by mass means $4\ g$ of $NaOH$ is present in $100\ g$ of solution.Mass of solute $(NaOH)$ $= 4\ g$.Molar mass of $NaOH = 23 + 16 + 1 = 40\ g/mol$.Moles of $NaOH = \frac{4\ g}{40\ g/mol} = 0.1\ mol$.Mass of solution $= 100\ g$.Density of solution $= 1.04\ g/mL$.Volume of solution $= \frac{	ext{Mass}}{	ext{Density}} = \frac{100\ g}{1.04\ g/mL} \approx 96.15\ mL$.Mass of solvent $= 	ext{Mass of solution} - 	ext{Mass of solute} = 100\ g - 4\ g = 96\ g = 0.096\ kg$.Molality $(m)$ $= \frac{	ext{Moles of solute}}{	ext{Mass of solvent in } kg} = \frac{0.1\ mol}{0.096\ kg} \approx 1.04\ m$.Since $1.04\ m > 1\ m$,the correct option is $C$.

The density of an aqueous solution of $4\%$ by mass $NaOH$ is $1.04\ g/mL$. The molality of the solution is:

Similar Questions

Mole fraction $(X)$ of any solution is equal to

Calculate the molarity of ethanol in a solution where the mole fraction of ethanol is $0.040$. (Assume the density of water is $1 \ g/mL$.) (in $M$)

What is the physical state of a solution containing camphor as the solute and $N_2$ gas as the solvent?

The volumes of two $HCl$ solutions $A$ $(0.5 \, M)$ and $B$ $(0.1 \, M)$ to be mixed for preparing $2 \, L$ of $0.2 \, M \, HCl$ are

In a solution of $7.8 \ g$ benzene $(C_6H_6)$ and $46.0 \ g$ toluene $(C_6H_5CH_3)$,the mole fraction of benzene in this solution is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module