Density of carbon monoxide is maximum at

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(B) From the ideal gas equation,density $\rho = \frac{PM}{RT}$.Since $M$ (molar mass) and $R$ (gas constant) are constant for carbon monoxide,we have

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$4 \ atm$ and $500 \ K$

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(B) From the ideal gas equation,density $\rho = \frac{PM}{RT}$.Since $M$ (molar mass) and $R$ (gas constant) are constant for carbon monoxide,we have $\rho \propto \frac{P}{T}$.We calculate the ratio $\frac{P}{T}$ for each option:$A$. $0.5 \ atm, 273 \ K$$\frac{0.5}{273} \approx 0.0018$$B$. $4 \ atm, 500 \ K$$\frac{4}{500} = 0.008$$C$. $2 \ atm, 600 \ K$$\frac{2}{600} \approx 0.0033$$D$. $6 \ atm, 1092 \ K$$\frac{6}{1092} \approx 0.0055$The ratio $\frac{P}{T}$ is highest for option $B$. Thus,the density is maximum at $4 \ atm$ and $500 \ K$.

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