Derive the unit of force using the second law | vedclass

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(C) According to Newton's second law of motion,$F = ma$. The $SI$ unit of force is $kg \, m s^{-2}$,which is defined as $1 \, N$.Given:Force $F = 5 \,

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$6$

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(C) According to Newton's second law of motion,$F = ma$. The $SI$ unit of force is $kg \, m s^{-2}$,which is defined as $1 \, N$.Given:Force $F = 5 \, N$Acceleration $a_1 = 8 \, m s^{-2}$ for mass $m_1$Acceleration $a_2 = 24 \, m s^{-2}$ for mass $m_2$Calculating individual masses:$m_1 = \frac{F}{a_1} = \frac{5}{8} \, kg$$m_2 = \frac{F}{a_2} = \frac{5}{24} \, kg$When both masses are tied together,the total mass $M$ is:$M = m_1 + m_2 = \frac{5}{8} + \frac{5}{24} = \frac{15 + 5}{24} = \frac{20}{24} = \frac{5}{6} \, kg$Acceleration $a$ produced by the same force $F$ on the combined mass $M$ is:$a = \frac{F}{M} = \frac{5}{5/6} = 6 \, m s^{-2}$

Derive the unit of force using the second law of motion. $A$ force of $5 \, N$ produces an acceleration of $8 \, m s^{-2}$ on a mass $m_1$ and an acceleration of $24 \, m s^{-2}$ on a mass $m_2$. What acceleration would the same force provide if both the masses are tied together (in $, m s^{-2}$)?

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