Determine the empirical formula of Kevlar,use | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Assume the total mass of the compound is $100 \ g$. Number of moles of $C = \frac{70.6 \ g}{12 \ g/mol} = 5.88 \ mol$. Number of moles of $H = \fr

Vedclass · Accepted Answer

$C_7H_5NO$

Vedclass · Answer

(D) Assume the total mass of the compound is $100 \ g$. Number of moles of $C = \frac{70.6 \ g}{12 \ g/mol} = 5.88 \ mol$. Number of moles of $H = \frac{4.2 \ g}{1 \ g/mol} = 4.2 \ mol$. Number of moles of $N = \frac{11.8 \ g}{14 \ g/mol} = 0.84 \ mol$. Number of moles of $O = \frac{13.4 \ g}{16 \ g/mol} = 0.84 \ mol$. Divide each by the smallest value $(0.84)$: $C = \frac{5.88}{0.84} = 7$ $H = \frac{4.2}{0.84} = 5$ $N = \frac{0.84}{0.84} = 1$ $O = \frac{0.84}{0.84} = 1$ Thus,the empirical formula is $C_7H_5NO$.

Determine the empirical formula of Kevlar,used in making bulletproof vests,if it contains $70.6 \% \, C, 4.2 \% \, H, 11.8 \% \, N$,and $13.4 \% \, O$.

Similar Questions

Which of the products is formed when acetone is reacted with barium hydroxide solution?

Explain the difference between Heartwood and Sapwood.

The arithmetic mean of a set of observations is $\bar{X}$. If each observation is divided by $\alpha$ and then increased by $10$,then the mean of the new series is:

All the diodes are ideal. The current flowing in the $2 \, \Omega$ resistor connected between the diodes $D_1$ and $D_2$ is .......... $A$

Two identical piano wires have a fundamental frequency of $600 \text{ Hz}$ when kept under the same tension. What fractional increase in the tension of one wire will lead to the occurrence of $6 \text{ beats per second}$ when both wires vibrate simultaneously?

Vedclass Test Series

Exam Paper Generator

Online Exam Module