Determine the point on the graph of the linea | vedclass

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Question

(A) Let the abscissa of the point be $x$ and the ordinate be $y$.According to the problem,the ordinate is $1 \frac{1}{2}$ times the abscissa,so $y = 1

Vedclass · Accepted Answer

($2$,$3$)

Vedclass · Answer

(A) Let the abscissa of the point be $x$ and the ordinate be $y$.According to the problem,the ordinate is $1 \frac{1}{2}$ times the abscissa,so $y = 1 \frac{1}{2} x = \frac{3}{2} x$.Substitute $y = \frac{3}{2} x$ into the given linear equation $2x + 5y = 19$:$2x + 5(\frac{3}{2} x) = 19$$2x + \frac{15}{2} x = 19$Multiply the entire equation by $2$ to clear the fraction:$4x + 15x = 38$$19x = 38$$x = 2$Now,find the ordinate $y$ using $y = \frac{3}{2} x$:$y = \frac{3}{2} (2) = 3$Thus,the point is $(2, 3)$.

Determine the point on the graph of the linear equation $2x + 5y = 19$,whose ordinate is $1 \frac{1}{2}$ times its abscissa.

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