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(B) $1$. In the jar,liquid $2$ is at the bottom and liquid $1$ is at the top,which implies that the density of liquid $2$ is greater than the density

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${\rho _1} < {\rho _3} < {\rho _2}$

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(B) $1$. In the jar,liquid $2$ is at the bottom and liquid $1$ is at the top,which implies that the density of liquid $2$ is greater than the density of liquid $1$ $({\rho _2} > {\rho _1})$.$2$. The solid ball is floating at the interface of the two liquids.$3$. Since the ball is partially submerged in liquid $1$ and partially in liquid $2$,its density ${\rho _3}$ must be greater than the density of the upper liquid $({\rho _3} > {\rho _1})$ and less than the density of the lower liquid $({\rho _3} $4$. Combining these inequalities,we get ${\rho _1} < {\rho _3} < {\rho _2}$.

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