The dielectric constant of pure water is 81. | vedclass

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Question

(A) The permittivity $\varepsilon$ of a medium is given by the formula $\varepsilon = K \varepsilon_0$,where $K$ is the dielectric constant and $\vare

Vedclass · Accepted Answer

$7.17 	imes 10^{-10} 	ext{ MKS units}$

Vedclass · Answer

(A) The permittivity $\varepsilon$ of a medium is given by the formula $\varepsilon = K \varepsilon_0$,where $K$ is the dielectric constant and $\varepsilon_0$ is the permittivity of free space.Given $K = 81$ and $\varepsilon_0 \approx 8.854 	imes 10^{-12} 	ext{ C}^2/	ext{N}\cdot	ext{m}^2$.Substituting the values: $\varepsilon = 81 	imes 8.854 	imes 10^{-12} 	ext{ C}^2/	ext{N}\cdot	ext{m}^2$.$\varepsilon \approx 717.174 	imes 10^{-12} 	ext{ C}^2/	ext{N}\cdot	ext{m}^2$.$\varepsilon \approx 7.17 	imes 10^{-10} 	ext{ C}^2/	ext{N}\cdot	ext{m}^2$ (or $MKS$ units).

The dielectric constant of pure water is $81$. Its permittivity will be:

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