The dimensional formula for angular momentum | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Angular momentum $(L)$ is defined as the product of linear momentum $(p)$ and the perpendicular distance $(r)$ from the axis of rotation.Mathemati

Vedclass · Accepted Answer

$M{L^2}{T^{ - 1}}$

Vedclass · Answer

(B) Angular momentum $(L)$ is defined as the product of linear momentum $(p)$ and the perpendicular distance $(r)$ from the axis of rotation.Mathematically,$L = p 	imes r$.Since linear momentum $p = m 	imes v$,where $m$ is mass and $v$ is velocity.The dimensional formula for mass $m$ is $[M]$.The dimensional formula for velocity $v$ is $[L{T^{ - 1}}]$.The dimensional formula for distance $r$ is $[L]$.Therefore,the dimensional formula for angular momentum is $[M] 	imes [L{T^{ - 1}}] 	imes [L] = [M{L^2}{T^{ - 1}}]$.

Column-$I$	Column-$II$
$(1)$ Torque	$(a)$ $M^1L^1T^{-1}$
$(2)$ Angular momentum	$(b)$ $M^1L^2T^{-1}$
$(3)$ Linear momentum	$(c)$ $M^1L^2T^{-2}$

The dimensional formula for angular momentum is

Similar Questions

The dimensions of the universal gravitational constant are:

The dimensional formula of heat energy is:

The wave equation is given by $Y = A \sin \omega \left( \frac{x}{v} - k \right)$,where $\omega$ is the angular velocity and $v$ is the linear velocity. What is the dimension of $k$?

Match the physical quantities in Column-$I$ with their corresponding dimensional formulas in Column-$II$.

Column-$I$ Column-$II$

$(1)$ Torque $(a)$ $M^1L^1T^{-1}$

$(2)$ Angular momentum $(b)$ $M^1L^2T^{-1}$

$(3)$ Linear momentum $(c)$ $M^1L^2T^{-2}$

The dimensions of resistance are the same as those of $......$ where $h$ is the Planck's constant and $e$ is the charge.

Vedclass Test Series

Exam Paper Generator

Online Exam Module