Dimensions of kinetic energy are

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Question

(A) The formula for kinetic energy is $K.E. = \frac{1}{2}mv^2$.Here,$m$ is mass,which has dimensions $[M]$.$v$ is velocity,which has dimensions $[LT^{

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$M{L^2}{T^{-2}}$

Vedclass · Answer

(A) The formula for kinetic energy is $K.E. = \frac{1}{2}mv^2$.Here,$m$ is mass,which has dimensions $[M]$.$v$ is velocity,which has dimensions $[LT^{-1}]$.Substituting these into the formula,we get:$[K.E.] = [M] 	imes [LT^{-1}]^2 = [M] 	imes [L^2T^{-2}] = [ML^2T^{-2}]$.Therefore,the dimensions of kinetic energy are $[ML^2T^{-2}]$.

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