Discuss the experiment verifying Newton's law of cooling.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Newton's law of cooling states that the rate of loss of heat is directly proportional to the difference in temperature between the body and its surroundings.
To verify this,an experimental setup is used consisting of a double-walled vessel $(V)$ containing water between the two walls to maintain a constant surrounding temperature.
$A$ copper calorimeter $(C)$ containing hot water is placed inside the double-walled vessel. The calorimeter is closed tightly with a cork having two holes.
Two thermometers are inserted through the corks to measure the temperature $T_{2}$ of the water in the calorimeter and the temperature $T_{1}$ of the water in the double-walled vessel,respectively.
The temperature of the hot water in the calorimeter is recorded at equal intervals of time. $A$ graph is plotted between $\log_{e}(T_{2} - T_{1})$ and time $(t)$.
The nature of the graph is observed to be a straight line with a negative slope,which confirms the relation $\log_{e}(T_{2} - T_{1}) = -Kt + C$,analogous to the linear equation $y = -mx + c$.

Explore More

Similar Questions

It takes $1 \, min$ for hot water to cool from $80^{\circ}C$ to $60^{\circ}C$. Find the time taken (in $sec$) to cool from $60^{\circ}C$ to $50^{\circ}C$. The temperature of the surroundings is $30^{\circ}C$.

Difficult
View Solution

For a small temperature difference between the body and the surroundings,the relation between the rate of loss of heat $R$ and the temperature of the body $\theta$ is depicted by:

$A$ body cools from $62^{\circ}C$ to $50^{\circ}C$ in $10$ minutes and to $42^{\circ}C$ in the next $10$ minutes. The temperature of the surrounding is ........ $^{\circ}C$.

Difficult
View Solution

$A$ heating element of mass $100 \,g$ and having specific heat of $1 \,J/(g^{\circ}C)$ is exposed to surrounding air at $27^{\circ}C$. The element attains a steady state temperature of $127^{\circ}C$, while absorbing $100 \,W$ of electric power. If the power is switched off, then the approximate time taken by the element to cool down to $126^{\circ}C$ will be (neglect radiation). (in $\,s$)

$A$ sphere of density $\rho$,specific heat capacity $c$,and radius $r$ is hung by a thermally insulating thread in an enclosure which is kept at a lower temperature than the sphere. The temperature of the sphere starts to drop at a rate which depends upon the temperature difference between the sphere and the enclosure and the nature of the surface of the sphere and is proportional to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo