Discuss the molecular structure of $BrF_3$ based on the $VSEPR$ theory.

(N/A) The central atom $Br$ has seven valence electrons. Three of these electrons form bond pairs with three fluorine atoms,leaving four electrons behind.
Thus,it contains three bond pairs and two lone pairs.
According to the $VSEPR$ theory,these are arranged at the corners of a trigonal bipyramid.
The two lone pairs occupy equatorial positions to minimize lone pair-lone pair and bond pair-lone pair repulsions,which are greater than bond pair-bond pair repulsions.
Additionally,the axial fluorine atoms bend towards the equatorial fluorine atom to minimize lone pair-lone pair repulsions.
Therefore,its shape is slightly bent,resembling a $'T'$ shape.