The distances of the point (1, 2, 3) from the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The distance of a point $P(x, y, z)$ from the coordinate axes is given by:$1$. Distance from the $x$-axis: $d_x = \sqrt{y^2 + z^2} = \sqrt{2^2 + 3

Vedclass · Accepted Answer

$\sqrt{13}, \sqrt{10}, \sqrt{5}$

Vedclass · Answer

(B) The distance of a point $P(x, y, z)$ from the coordinate axes is given by:$1$. Distance from the $x$-axis: $d_x = \sqrt{y^2 + z^2} = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13}$.$2$. Distance from the $y$-axis: $d_y = \sqrt{x^2 + z^2} = \sqrt{1^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10}$.$3$. Distance from the $z$-axis: $d_z = \sqrt{x^2 + y^2} = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5}$.Thus,the distances are $\sqrt{13}, \sqrt{10}, \sqrt{5}$.

The distances of the point $(1, 2, 3)$ from the coordinate axes are:

Similar Questions

Find the distance between the following pairs of points: $(-1, 3, -4)$ and $(1, -3, 4)$.

In the figure,if $P$ is $(2, 4, 5)$,find the coordinates of $F$.

If the coordinates of points $A$ and $B$ are $(3, 4, 5)$ and $(-1, 3, -7)$ respectively,find the equation of the locus of point $P(x, y, z)$ such that $PA^2 - PB^2 + 2k^2 = 0$.

How far apart are the points $(2,0,0)$ and $(-3,0,0)$?

If the extremities of a diagonal of a square are $(1, -2, 3)$ and $(2, -3, 5)$,then the length of its side is

Vedclass Test Series

Exam Paper Generator

Online Exam Module