Divide the polynomial 4y^{3}-3y^{2}+2y-4 by y | vedclass

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Question

(A) To divide $4y^{3}-3y^{2}+2y-4$ by $y+2$:$1$. Divide the first term $4y^{3}$ by $y$ to get $4y^{2}$.$2$. Multiply $4y^{2}$ by $(y+2)$ to get $4y^{3

Vedclass · Accepted Answer

$4y^{2}-11y+24, -52$

Vedclass · Answer

(A) To divide $4y^{3}-3y^{2}+2y-4$ by $y+2$:$1$. Divide the first term $4y^{3}$ by $y$ to get $4y^{2}$.$2$. Multiply $4y^{2}$ by $(y+2)$ to get $4y^{3}+8y^{2}$. Subtract this from the dividend to get $-11y^{2}+2y-4$.$3$. Divide $-11y^{2}$ by $y$ to get $-11y$.$4$. Multiply $-11y$ by $(y+2)$ to get $-11y^{2}-22y$. Subtract this to get $24y-4$.$5$. Divide $24y$ by $y$ to get $24$.$6$. Multiply $24$ by $(y+2)$ to get $24y+48$. Subtract this to get $-52$.Therefore,the quotient is $4y^{2}-11y+24$ and the remainder is $-52$.

Divide the polynomial $4y^{3}-3y^{2}+2y-4$ by $y+2$ and find the quotient and remainder.

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