Does the escape speed of a body from the Earth depend on:
$(a)$ the mass of the body,
$(b)$ the location from where it is projected,
$(c)$ the direction of projection,
$(d)$ the height of the location from where the body is launched?

(D) No.
$(b)$ No.
$(c)$ No.
$(d)$ Yes.
The escape velocity $v_{esc}$ of a body from the Earth is given by the formula:
$v_{esc} = \sqrt{\frac{2GM}{R+h}}$
where $G$ is the gravitational constant,$M$ is the mass of the Earth,$R$ is the radius of the Earth,and $h$ is the height of the location from the surface.
$1$. It is clear from the formula that $v_{esc}$ is independent of the mass of the body $(m)$.
$2$. It is independent of the direction of projection as long as it is not directed into the Earth.
$3$. It depends on the location $(R+h)$ from where the body is launched. As the height $h$ increases,the escape velocity decreases.