Draw a circuit diagram of an electric circuit containing a cell,a key,an ammeter,a resistor of $2\,\Omega$ in series with a combination of two resistors ($4\,\Omega$ each) in parallel and a voltmeter across the parallel combination. Will the potential difference across the $2\,\Omega$ resistor be the same as that across the parallel combination of $4\,\Omega$ resistors? Give reason.

(A) Yes,the potential difference will be the same.
First,calculate the equivalent resistance of the parallel combination of two $4\,\Omega$ resistors:
$\frac{1}{R_p} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2}$
So,$R_p = 2\,\Omega$.
Since the $2\,\Omega$ resistor is in series with the parallel combination (which also has an equivalent resistance of $2\,\Omega$),the same current $I$ flows through both. According to Ohm's Law $(V = IR)$,since the resistance values are equal $(2\,\Omega = 2\,\Omega)$ and the current $I$ is the same,the potential difference across both will be equal.