Draw the graphs of the pair of linear equatio | vedclass

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(C) $1$. For the equation $x+y=10$,if $x=0, y=10$; if $y=0, x=10$. The line passes through $(0,10)$ and $(10,0)$.$2$. For the equation $x-y=4$,if $x=0

Vedclass · Accepted Answer

$(7,3), (4,0), (10,0)$

Vedclass · Answer

(C) $1$. For the equation $x+y=10$,if $x=0, y=10$; if $y=0, x=10$. The line passes through $(0,10)$ and $(10,0)$.$2$. For the equation $x-y=4$,if $x=0, y=-4$; if $y=0, x=4$. The line passes through $(0,-4)$ and $(4,0)$.$3$. Solving the equations simultaneously: Adding $(x+y=10)$ and $(x-y=4)$ gives $2x=14$,so $x=7$. Substituting $x=7$ into $x+y=10$ gives $y=3$. The intersection point is $(7,3)$.$4$. The triangle is formed by the intersection of the two lines $(7,3)$ and their respective intersections with the $X$-axis,which are $(4,0)$ and $(10,0)$.$5$. Thus,the vertices of the triangle are $(7,3), (4,0),$ and $(10,0)$.

Draw the graphs of the pair of linear equations $x+y=10$ and $x-y=4$. Determine the coordinates of the vertices of the triangle formed by these linear equations and the $X$-axis.

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