During the capillary rise of a liquid in a capillary tube,the surface of contact that remains constant is of

The heat evolved for the rise of water when one end of the capillary tube of radius $r$ is immersed vertically into water is (Assume surface tension $= T$ and density of water to be $\rho$)

The radii of the two columns in a $U$ tube are $r_1$ and $r_2$. When a liquid of density $\rho$ (angle of contact is $0^o$) is filled in it,the level difference of liquid in the two arms is $h$. The surface tension of the liquid is ($g =$ acceleration due to gravity):

Water rises up to a height $h$ in a capillary tube of a certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now,the water will rise to a height of:

Two capillaries made of the same material but of different radii are dipped in a liquid. The rise of liquid in one capillary is $2.2 \ cm$ and that in the other is $6.6 \ cm$. The ratio of their radii is

If a capillary experiment is performed in a vacuum,what happens to the liquid level in the capillary tube?