During the change of O_2 to O_2^- ion,the ele | vedclass

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(A) The electronic configuration of $O_2$ is $KK \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 \pi(2p_y)^2 \pi^*(2p_x)^1 \pi^*(2p_y)^1$.When

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$\pi ^*$ orbital

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(A) The electronic configuration of $O_2$ is $KK \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 \pi(2p_y)^2 \pi^*(2p_x)^1 \pi^*(2p_y)^1$.When $O_2$ gains an electron to form $O_2^-$,the incoming electron enters the next available orbital,which is the antibonding $\pi^*$ orbital.Thus,the configuration of $O_2^-$ becomes $KK \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 \pi(2p_y)^2 \pi^*(2p_x)^2 \pi^*(2p_y)^1$.

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

During the change of $O_2$ to $O_2^-$ ion,the electron adds to which one of the following orbitals?

Similar Questions

Which of the following species has a bond order of $1.5$?

The number of antibonding electron pairs in $O_2^{2-}$ molecular ion on the basis of molecular orbital theory is

Which of the following is not paramagnetic?

Match the following:

Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

Sum of bond order of $CO$ and $NO^{+}$ is $ . . . . . . $.

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