During the adsorption of a gas on a solid at | vedclass

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Question

(A) Adsorption is a spontaneous process,so $\Delta G < 0$.It is an exothermic process,which means heat is released,so $\Delta H < 0$.As gas molecules

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$\Delta G < 0, \Delta H < 0, \Delta S < 0$

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(A) Adsorption is a spontaneous process,so $\Delta G It is an exothermic process,which means heat is released,so $\Delta H As gas molecules get adsorbed on the solid surface,their freedom of movement decreases,leading to a decrease in entropy,so $\Delta S According to the Gibbs-Helmholtz equation,$\Delta G = \Delta H - T \Delta S$. At low temperatures,the negative $\Delta H$ term dominates,ensuring $\Delta G < 0$.

During the adsorption of a gas on a solid at low temperature,which of the following thermodynamic conditions is correct?

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