During the adsorption of a gas on the surface | vedclass

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(B) During the adsorption of a gas on the surface of a solid,there is a decrease in surface energy,which means it is an exothermic process. Therefore,

Vedclass · Accepted Answer

$\Delta G < 0, \Delta H < 0, \Delta S < 0$

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(B) During the adsorption of a gas on the surface of a solid,there is a decrease in surface energy,which means it is an exothermic process. Therefore,$\Delta H When a gas is adsorbed,the freedom of movement of its molecules becomes restricted,leading to a decrease in the entropy of the system. Therefore,$\Delta S According to the Gibbs free energy equation,$\Delta G = \Delta H - T \Delta S$. For a spontaneous process,$\Delta G$ must be negative. Since adsorption is a spontaneous process,$\Delta G < 0$.

During the adsorption of a gas on the surface of a solid,which of the following is true?

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