During the electrolysis of aqueous NaCl (brin | vedclass

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(D) $1$. Aqueous $NaCl$ contains $Na^+$, $Cl^-$, $H^+$, and $OH^-$ ions.$2$. At the cathode, the reduction reaction with the higher standard reduction

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$H_{2(g)}$

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(D) $1$. Aqueous $NaCl$ contains $Na^+$, $Cl^-$, $H^+$, and $OH^-$ ions.$2$. At the cathode, the reduction reaction with the higher standard reduction potential occurs.$3$. The reduction potential of $H^+ + e^- ightarrow \frac{1}{2} H_{2(g)}$ $(E^0 = 0.00 	ext{ V})$ is higher than that of $Na^+ + e^- ightarrow Na_{(s)}$ $(E^0 = -2.71 	ext{ V})$.$4$. Therefore, $H^+$ ions are reduced to $H_{2(g)}$ gas at the cathode.

During the electrolysis of aqueous $NaCl$ (brine), the product formed at the cathode is?

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