During the first year,the population of a vil | vedclass

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(B) Let the initial population at the beginning of the first year be $a$.According to the problem:First year increase: $a 	imes (1 + \frac{5}{100}) =

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$48000$

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(B) Let the initial population at the beginning of the first year be $a$.According to the problem:First year increase: $a 	imes (1 + \frac{5}{100}) = a 	imes \frac{105}{100} = a 	imes \frac{21}{20}$.Second year decrease: $(a 	imes \frac{21}{20}) 	imes (1 - \frac{5}{100}) = (a 	imes \frac{21}{20}) 	imes \frac{95}{100} = (a 	imes \frac{21}{20}) 	imes \frac{19}{20}$.Given that the final population is $47880$:$a 	imes \frac{21}{20} 	imes \frac{19}{20} = 47880$.$a 	imes \frac{399}{400} = 47880$.$a = \frac{47880 	imes 400}{399}$.$a = 120 	imes 400 = 48000$.Therefore,the population at the beginning of the first year was $48000$.

During the first year,the population of a village is increased by $5 \%$ and in the second year it is diminished by $5 \%$. At the end of the second year,its population was $47880$. What was the population at the beginning of the first year?

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