During the propagation of a nerve impulse,the action potential results from the movement of

  • A
    $K^+$ ions from intracellular fluid to extracellular fluid
  • B
    $Na^+$ ions from extracellular fluid to intracellular fluid
  • C
    $K^+$ ions from extracellular fluid to extracellular fluid
  • D
    $Na^+$ ions from intracellular fluid to extracellular fluid

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Similar Questions

Select the correct sequence of statements regarding the conduction of a nerve impulse and select the correct option given below.
$i.$ Rapid influx of $Na^{+}$ inside the axon.
$ii.$ $Na^{+}$ gates are closed and $K^{+}$ gates open after the refractory period.
$iii.$ Intracellular fluid is electronegative and the potential difference is $-70 \ mV$.
$iv.$ Extracellular fluid becomes electronegative.
$v.$ Disturbance to the resting potential.

For the propagation of a nerve impulse along a nerve fiber,what is the sequence of change in the electrical potential difference across the axolemma?

$A$: In the nervous system,the generation of an action potential depends upon the influx of sodium ions into the axoplasm.
$R$: The influx of sodium ions during nerve impulse generation is due to the efflux of potassium ions.

When an impulse passes,the membrane is depolarized and the charge of the cells is

When a neuron is not conducting any impulse,$i.e$.,resting,the axonal membrane is comparatively more permeable to:

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