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(C) The alphabet series is given as $A$ to $Z$.First,we identify the letter that is fourth to the left of $I$.Counting backwards from $I$ ($I=9^{th}$

Vedclass · Accepted Answer

$U$

Vedclass · Answer

(C) The alphabet series is given as $A$ to $Z$.First,we identify the letter that is fourth to the left of $I$.Counting backwards from $I$ ($I=9^{th}$ letter): $H(8), G(7), F(6), E(5)$. So,the fourth letter to the left of $I$ is $E$.Next,we find the sixteenth letter to the right of $E$.Since $E$ is the $5^{th}$ letter,the sixteenth letter to its right is $5 + 16 = 21^{st}$ letter.The $21^{st}$ letter in the English alphabet is $U$.

Each of the following questions is based on the following alphabet series.
$A, B, C, D, E, F, G, H, I, J, K, L, M$
$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$
Which letter is sixteenth to the right of the letter which is fourth to the left of $I$?

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Each of the following questions is based on the following alphabet series.$A, B, C, D, E, F, G, H, I, J, K, L, M$$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$Which letter is sixteenth to the right of the letter which is fourth to the left of $I$?