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(B) The original alphabet series is $A$ to $Z$.When written in reverse order,the series becomes $Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I,

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$N$

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(B) The original alphabet series is $A$ to $Z$.When written in reverse order,the series becomes $Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I, H, G, F, E, D, C, B, A$.The ninth letter from the right in the reverse series is the same as the ninth letter from the left in the original series,which is $I$.To find the fifth letter to the left of the ninth letter from the right $(I)$,we count five positions to the left of $I$ in the reverse series: $H, G, F, E, D$.Alternatively,using the position formula: The ninth letter from the right is at position $9$ from the right. The fifth letter to the left of this position is $9 + 5 = 14$th letter from the right.The $14$th letter from the right in the reverse series is the $14$th letter from the left in the original series,which is $N$.

Each of the following questions is based on the following alphabet series.
$A, B, C, D, E, F, G, H, I, J, K, L, M$
$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$
If the above alphabets were written in the reverse order,which will be the fifth letter to the left of the ninth letter from the right?

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Each of the following questions is based on the following alphabet series.$A, B, C, D, E, F, G, H, I, J, K, L, M$$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$If the above alphabets were written in the reverse order,which will be the fifth letter to the left of the ninth letter from the right?