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(C) The original alphabet is $A$ to $Z$. When written in reverse order,the series becomes $Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I, H, G,

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$W$

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(C) The original alphabet is $A$ to $Z$. When written in reverse order,the series becomes $Z, Y, X, W, V, U, T, S, R, Q, P, O, N, M, L, K, J, I, H, G, F, E, D, C, B, A$.The sixteenth letter from the left in this reversed series is the $16^{th}$ letter of the sequence $Z, Y, X, ...$.Counting from the left ($Z$ is $1^{st}$,$Y$ is $2^{nd}$,...,$K$ is $16^{th}$),the $16^{th}$ letter is $K$.Now,we need to find the twelfth letter to the left of $K$.Since we are already at $K$ (which is the $16^{th}$ position from the left),moving to the left means moving towards the beginning of the reversed series $(Z)$.Position of $K$ is $16$. Moving $12$ places to the left means $16 - 12 = 4$.The $4^{th}$ letter from the left in the reversed series is $W$ $(Z=1, Y=2, X=3, W=4)$.

Each of the following questions is based on the following alphabet series.
$A, B, C, D, E, F, G, H, I, J, K, L, M$
$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$
If the above alphabet is written in the reverse order,which letter will be the twelfth to the left of the sixteenth letter from your left?

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Each of the following questions is based on the following alphabet series.$A, B, C, D, E, F, G, H, I, J, K, L, M$$N, O, P, Q, R, S, T, U, V, W, X, Y, Z$If the above alphabet is written in the reverse order,which letter will be the twelfth to the left of the sixteenth letter from your left?