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Question

(A) Let the total rent of the car be $x$.When $8$ persons share the rent,the share of each person is $\frac{x}{8}$.When one person withdraws,the numbe

Vedclass · Accepted Answer

$\frac{1}{7}$

Vedclass · Answer

(A) Let the total rent of the car be $x$.When $8$ persons share the rent,the share of each person is $\frac{x}{8}$.When one person withdraws,the number of persons remaining is $8 - 1 = 7$.Now,the share of each of the $7$ persons is $\frac{x}{7}$.The increase in the share of each person is $\frac{x}{7} - \frac{x}{8} = \frac{8x - 7x}{56} = \frac{x}{56}$.To find the fraction by which the share increases,we divide the increase by the original share:$	ext{Increase fraction} = \frac{\frac{x}{56}}{\frac{x}{8}} = \frac{x}{56} 	imes \frac{8}{x} = \frac{8}{56} = \frac{1}{7}$.

Eight persons are planning to share equally the rent of a car. If one person withdraws from the arrangement and the others share equally the entire cost of the car,then the share of each of the remaining persons increases by what fraction?

Similar Questions

$\frac{0.0203 \times 2.92}{0.0073 \times 14.5 \times 0.7} = ?$

What is the value of $(2.3+1.7)^{2}-(2.3-1.7)^{2} ?$

The simplification of $1+\frac{1}{1+\frac{1}{1-\frac{2}{3}}}$ yields the result

Simplify:
$\frac{3}{10} \div \frac{3}{7} \text{ of } \left(2 \frac{3}{10} + 2 \frac{3}{5}\right) + \frac{1}{5} \div 1 \frac{2}{5} - \frac{2}{7}$

$138.009 + 341.981 - 146.305 = 123.6 + ?$

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