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(A) The electric field is given by $\overrightarrow{E} = a \hat{i} + b \hat{j}$.The area vector $\overrightarrow{A}$ for a square of side $l$ parallel

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$a l^2$

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(A) The electric field is given by $\overrightarrow{E} = a \hat{i} + b \hat{j}$.The area vector $\overrightarrow{A}$ for a square of side $l$ parallel to the $y-z$ plane is directed along the $x$-axis,so $\overrightarrow{A} = l^2 \hat{i}$.The electric flux $\Phi$ is defined as the dot product of the electric field and the area vector: $\Phi = \overrightarrow{E} \cdot \overrightarrow{A}$.Substituting the values: $\Phi = (a \hat{i} + b \hat{j}) \cdot (l^2 \hat{i})$.Since $\hat{i} \cdot \hat{i} = 1$ and $\hat{j} \cdot \hat{i} = 0$,we get $\Phi = a l^2 (1) + b l^2 (0) = a l^2$.Therefore,the net flux is $a l^2$.

Electric field in a region is given by $\overrightarrow{E} = a \hat{i} + b \hat{j}$,where $a$ and $b$ are constants. The net flux passing through a square area of side $l$ parallel to the $y-z$ plane is

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