Electrolysis of concentrated aqueous solution | vedclass

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Question

(A) The electrolysis of concentrated aqueous $NaCl$ (brine) involves the following half-reactions: At the cathode: $2 H_2O(l) + 2 e^{-} \longrightarro

Vedclass · Accepted Answer

increase in $pH$ of the solution

Vedclass · Answer

(A) The electrolysis of concentrated aqueous $NaCl$ (brine) involves the following half-reactions: At the cathode: $2 H_2O(l) + 2 e^{-} \longrightarrow H_2(g) + 2 OH^{-}(aq)$ At the anode: $2 Cl^{-}(aq) \longrightarrow Cl_2(g) + 2 e^{-}$ The overall reaction is: $2 NaCl(aq) + 2 H_2O(l) \longrightarrow 2 NaOH(aq) + H_2(g) + Cl_2(g)$ Since $NaOH$ is produced in the solution,the concentration of $OH^{-}$ ions increases,which leads to an increase in the $pH$ of the solution. Thus,the correct option is $A$.

Electrolysis of concentrated aqueous solution of $NaCl$ results in

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