During the light reaction,electrons are transferred by the splitting of $H_2O$ through the $ETC$,which results in the reduction of:

  • A
    $NAD$ to $NADH + H^+$
  • B
    $NADPH$ to $H^+$
  • C
    $NADP^+$ to $NADPH + H^+$
  • D
    $NAD$ to $NADPH + H^+$

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