Eleven years earlier,the average age of a fam | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Eleven years ago,the total age of $4$ members was $4 	imes 28 = 112 \, 	ext{years}$.$2$. Presently,these $4$ members have aged by $11$ year

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) $1$. Eleven years ago,the total age of $4$ members was $4 	imes 28 = 112 \, 	ext{years}$.$2$. Presently,these $4$ members have aged by $11$ years each,so their total age is $112 + (4 	imes 11) = 112 + 44 = 156 \, 	ext{years}$.$3$. Currently,the family has $6$ members,and their average age is $28 \, 	ext{years}$. Thus,the total age of the $6$ members is $6 	imes 28 = 168 \, 	ext{years}$.$4$. The sum of the ages of the $2$ children is $168 - 156 = 12 \, 	ext{years}$.$5$. Let the present age of the youngest child be $x$. Since the children were born within the last $11$ years,the elder child's age is $x + k$,where $k$ is the age gap.$6$. The problem states that at the time of the birth of the youngest child,the elder child's age was equal to the total number of family members $(6)$.$7$. Let $t$ be the time elapsed since the birth of the youngest child. Then the youngest child's age is $t$,and the elder child's age is $6 + t$. $8$. The sum of their ages is $t + (6 + t) = 12 \Rightarrow 2t + 6 = 12 \Rightarrow 2t = 6 \Rightarrow t = 3$.$9$. Thus,the present age of the youngest member is $3 \, 	ext{years}$.

Similar Questions

The average marks of $120$ students are $35.$ If the average of passed students was $39$ and failed students was $15,$ then find the number of students who have passed.

The average of two numbers is $62$. If $2$ is added to the smaller number,the ratio between the numbers becomes $1:2$. The smaller number is

The average of three numbers is $154$. The first number is twice the second and the second number is twice the third. The first number is

The arithmetic mean of $100$ observations is $24$. If $6$ is added to each of the observations and then each of them is multiplied by $2.5$,find the new arithmetic mean.

If the mean of $a, b, c$ is $M$ and $ab + bc + ca = 0$,then the mean of $a^2, b^2, c^2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module