The elimination reaction of 2-bromopentane to | vedclass

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Question

(B) The reaction of $2-$bromopentane with a base (like $NaOEt$) to form pent$-2-$ene is a $\beta-$elimination reaction.In this process,a hydrogen atom

Vedclass · Accepted Answer

$a, b, c$

Vedclass · Answer

(B) The reaction of $2-$bromopentane with a base (like $NaOEt$) to form pent$-2-$ene is a $\beta-$elimination reaction.In this process,a hydrogen atom is removed from the $\beta-$carbon and a halogen atom is removed from the $\alpha-$carbon,which is known as dehydrohalogenation.Since the major product formed is the more substituted alkene (pent$-2-$ene),the reaction follows Zaitsev rule.Dehydration refers to the removal of water,which is not the case here.Therefore,statements $a$,$b$,and $c$ are correct.

The elimination reaction of $2-$bromopentane to form pent$-2-$ene involves:
$a$. $\beta-$Elimination reaction
$b$. Following Zaitsev rule
$c$. Dehydrohalogenation reaction
$d$. Dehydration reaction

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The elimination reaction of $2-$bromopentane to form pent$-2-$ene involves:$a$. $\beta-$Elimination reaction$b$. Following Zaitsev rule$c$. Dehydrohalogenation reaction$d$. Dehydration reaction