(C) The process described is $\beta^-$-decay,where a neutron transforms into a proton and an electron: $_0n^1 \to _{+1}p^1 + _{-1}e^0$. Since the atom

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Nuclear charge higher by one unit

(C) The process described is $\beta^-$-decay,where a neutron transforms into a proton and an electron: $_0n^1 \to _{+1}p^1 + _{-1}e^0$. Since the atomic number $(Z)$ is equal to the number of protons,the transformation of a neutron into a proton increases the atomic number by $1$. Therefore,the new element formed has a nuclear charge higher by one unit.

Class 12 Chemistry Nuclear Chemistry Nucleus (Stability and Reaction)

Medium

Emission is caused by the transformation of one neutron into a proton. This results in the formation of a new element having

A
Same nuclear charge
B
Very lower nuclear charge
C
Nuclear charge higher by one unit
D
Nuclear charge lower by one unit

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Nuclear Chemistry

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Nucleus (Stability and Reaction)

$_{92}U^{238}$ emits $8$ $\alpha$-particles and $6$ $\beta$-particles. The neutron/proton ratio in the product nucleus is

MediumAIIMS 2005

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An atomic nucleus having a low $n/p$ ratio tries to find stability by:

EasyWBJEE 2014

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In the successive emission of $\alpha$- and $\beta$-particles,the number of $\alpha$- and $\beta$-particles that should be emitted for the conversion of ${}^{238}_{92}U$ to ${}^{206}_{82}Pb$ are:

MediumMHT CET 2008

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Hydrogen can be fused to form helium at

Easy

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Positron emission results from the transformation of one nuclear proton into a neutron. The isotope thus produced possesses

Medium

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Emission is caused by the transformation of one neutron into a proton. This results in the formation of a new element having

Similar Questions

$_{92}U^{238}$ emits $8$ $\alpha$-particles and $6$ $\beta$-particles. The neutron/proton ratio in the product nucleus is

An atomic nucleus having a low $n/p$ ratio tries to find stability by:

In the successive emission of $\alpha$- and $\beta$-particles,the number of $\alpha$- and $\beta$-particles that should be emitted for the conversion of ${}^{238}_{92}U$ to ${}^{206}_{82}Pb$ are:

Hydrogen can be fused to form helium at

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